2.2.3.10 PropertyNode

Name

PropertyNode

Remark

Hierarchy

• PropertyNode
  • TreeNode

Examples

Example 1: Scalars and strings

void propnode_scalars_demo()
{
    // A PropertyNode typically lives inside a Tree/TreeNode.
    Tree tr;
    TreeNode tn = tr.AddNode("settings");

    PropertyNode pn;                // create a node
    pn.nVal    = 42;               // int
    pn.dVal    = 3.14159;          // double
    pn.strVal  = "hello";          // string

    // attach PropertyNode to the tree node's "Value" payload
    tn.Value = pn;

    // read back
    PropertyNode got = tn.Value;
    printf("nVal=%d, dVal=%g, strVal=%s\n", got.nVal, got.dVal, got.strVal);
}

Example 2: Vectors

void propnode_vectors_demo()
{
    Tree tr;
    TreeNode tn = tr.AddNode("params");

    PropertyNode pn;
    pn.nVals.SetSize(3); pn.nVals[0] = 1; pn.nVals[1] = 2; pn.nVals[2] = 3;
    pn.dVals = {1.0, 2.5, 7.25};         // doubles
    pn.strVals = {"red","green","blue"}; // strings

    tn.Value = pn;

    // iterate integer vector
    PropertyNode got = tn.Value;
    for (int i = 0; i < got.nVals.GetSize(); i++)
        printf("nVals[%d]=%d\n", i, got.nVals[i]);
}

Example 3: Matrices (2D arrays)

void propnode_matrices_demo()
{
    Tree tr;
    TreeNode tn = tr.AddNode("grid");

    PropertyNode pn;
    pn.dVals2.SetSize(2,3); // 2 rows x 3 cols
    pn.dVals2[0][0] = 10; pn.dVals2[0][1] = 11; pn.dVals2[0][2] = 12;
    pn.dVals2[1][0] = 20; pn.dVals2[1][1] = 21; pn.dVals2[1][2] = 22;

    tn.Value = pn;

    // read back a single element
    double v = ((PropertyNode)tn.Value).dVals2[1][2]; // -> 22
    out_double("grid[1][2] = ", v);
}

Header to Include

origin.h

Reference

Members

Property